# HumanEval/37
# Loki Mode Multi-Agent Solution
# Attempts: 1
# Passed: True

def sort_even(l: list):
    """This function takes a list l and returns a list l' such that
    l' is identical to l in the odd indicies, while its values at the even indicies are equal
    to the values of the even indicies of l, but sorted.
    >>> sort_even([1, 2, 3])
    [1, 2, 3]
    >>> sort_even([5, 6, 3, 4])
    [3, 6, 5, 4]
    """
    even_elements = sorted(l[::2])
    result = l[:]
    for i, val in enumerate(even_elements):
        result[i * 2] = val
    return result